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Code fix · 4 checks · max 600 tokens · benched 2026-09-16

GPT-5.5 vs GPT-5.4 vs GPT-5.4 mini vs GPT-5.4 Nano vs GPT-5.3-Codex on fix an off-by-one in python

OpenAI models side by side on "Fix an off-by-one in Python": GPT-5.4 Nano scores 10/10; GPT-5.4 Nano is the cheapest answer scoring 8+ at $0.06 per 1,000 runs. Outputs, checks, judge reasons, latency and cost.

The prompt every model received

System

You are a senior engineer. Reply with code only unless asked otherwise.

User

This function should return the arithmetic mean of a non-empty list of numbers, but its result is wrong. Fix the bug with the smallest possible change and return the complete corrected function only, in a Python code block.

def average(nums):
    total = 0
    for n in nums:
        total += n
    return total / (len(nums) - 1)

Rubric for the judge: Returns the full function with the divisor corrected to len(nums) and no other behavioural changes.

Side by side

Every cell is one OpenRouter call at temperature 0 with the prompt's token cap and reasoning effort "low" where the model supports it. Cost is usage × the catalogue rate in models.json. Quality is one judge call to anthropic/claude-haiku-4.5 against the prompt's rubric, cached per prompt version.

GPT-5.5

openai/gpt-5.5

10/10
Latency
441ms
Cost
$0.00158
Per 1,000
$1.58

100 in · 36 out · 18 words · checks 4/4

  • contains
  • regex
  • not_contains
  • not_contains
```python
def average(nums):
    total = 0
    for n in nums:
        total += n
    return total / len(nums)
```

Judge: The output correctly fixes the bug by changing the divisor from len(nums) - 1 to len(nums), returns the complete function in a Python code block, and makes no other changes.

GPT-5.4

openai/gpt-5.4

10/10
Latency
397ms
Cost
$0.00079
Per 1,000
$0.79

100 in · 36 out · 18 words · checks 4/4

  • contains
  • regex
  • not_contains
  • not_contains
```python
def average(nums):
    total = 0
    for n in nums:
        total += n
    return total / len(nums)
```

Judge: The output correctly fixes the bug by changing the divisor from len(nums) - 1 to len(nums), returns the complete function in a Python code block, and makes no other changes.

GPT-5.4 mini

openai/gpt-5.4-mini

10/10
Latency
543ms
Cost
$0.00036
Per 1,000
$0.36

100 in · 64 out (26 reasoning) · 18 words · checks 4/4

  • contains
  • regex
  • not_contains
  • not_contains
```python
def average(nums):
    total = 0
    for n in nums:
        total += n
    return total / len(nums)
```

Judge: The output correctly fixes the bug by changing the divisor from len(nums) - 1 to len(nums), returns the complete function in a Python code block, and makes no other changes.

GPT-5.4 Nano

openai/gpt-5.4-nano

10/10
top judge scorecheapest scoring 8+
Latency
273ms
Cost
$6.5e-5
Per 1,000
$0.06

100 in · 36 out · 18 words · checks 4/4

  • contains
  • regex
  • not_contains
  • not_contains
```python
def average(nums):
    total = 0
    for n in nums:
        total += n
    return total / len(nums)
```

Judge: The output correctly fixes the bug by changing the divisor from len(nums) - 1 to len(nums), returns the complete function in a Python code block, and makes no other changes.

GPT-5.3-Codex

openai/gpt-5.3-codex

10/10
Latency
910ms
Cost
$0.00068
Per 1,000
$0.68

100 in · 36 out · 18 words · checks 4/4

  • contains
  • regex
  • not_contains
  • not_contains
```python
def average(nums):
    total = 0
    for n in nums:
        total += n
    return total / len(nums)
```

Judge: The output correctly fixes the bug by changing the divisor from len(nums) - 1 to len(nums), returns the complete function in a Python code block, and makes no other changes.

Frequently asked

What does this prompt test?

Code fix: Returns the full function with the divisor corrected to len(nums) and no other behavioural changes. The deterministic checks are contains, regex, not_contains, not_contains.

Which model should I pick for this task?

If the judge's bar of 8/10 is good enough for you, GPT-5.4 Nano at $0.06 per 1,000 runs. If you need the top score, GPT-5.4 Nano at $0.06 per 1,000 runs.

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